Binomial Theorem#
(1 + x)^2 = 1 + 2x + x^2.
(1 + x)^3 = 1 + 3x + 3x^2 + x^3.
What do you get when you expand (1+x)^n?
(1+ x)^n = \sum _{i =0} ^{n} \binom{n}{i} x^i
Last update: April 2, 2021
(1 + x)^2 = 1 + 2x + x^2.
(1 + x)^3 = 1 + 3x + 3x^2 + x^3.
What do you get when you expand (1+x)^n?